<PRE><B>Question 595095</B>
x1		y1	x2	y2			
3		4	1	-2			
							
slope m =		(y2-y1)/(x2-x1)					
(	-2	-	4	)/(	1	-	3
(	-6	/	-2	)  			
m=		3    					
The required line passes through both the points. So we select one point and plug it with the slope 							
Plug value of  the slope  and point			(	3	,	4	) in
Y	=	m	x	+	b		
4.00	=	3    	*	3	+	b	
4.00	=	9    	+	b			
b=	4    	+	-5    				
b=	9      						
So the equation  will be							
Y 	=	3 x	-5    		
m.ananth@hotmail.ca							
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