Question 594706
the sum of the digits of a two digit number is 8. When the number with the same digits reversed is subtracted from the number,the answer is 18. Find the number
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let t=ten's digit of original number
let u=unit digit of original number
t+u=8
u=8-t
..
10t+u-(10u+t)=18
10t+8-t-(10(8-t)+t)=18
10t+8-t-(80-10t+t)=18
10t+8-t-80+10t-t=18
18t=90
t=5
u=8-t=3
ans:
original number=10t+u=50+3=53