<PRE><B>Question 594534</B>
3 out of 10 houses have no insurance. if 6 houses are chosen at random what is the probability that exactly one will be uninsured
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Binomial Problem with n = 6 and p(insured) = 0.3
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P(x=1) = 6C1*0.3*0.7^5
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P(x=1) = 6*0.3*0.1681 = 0.3025
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Cheers,
Stan H.
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