Question 594455
i am gonna give you a little background about factorization. 
let's say you have a function x^2+ax+ b, its factorization is (x- c)(x-d), where c*d = 48, and c+d = -a.

with that in mind, we have to find two numbers ( if they exist) whose product is 48 and their sum is 2.

(1, 48)  (2, 24) (3, 16)  (4, 12) (6, 8) are the only pair of integers whose product of its element is  48; but none  of those pair has elements whose sum is 2 , thus  that function is not factorisable. 
From an 8th grade approach it is not  factorisable.
  
 however, that function IS factorisable with complex numbers.