Question 594224
There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? 
I did 11x5 and got 55 but I dont think that is right.
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Ans: 11C5 = 11!/(6!*5!) = (11*10*9*8*7)/(1*2*3*4*5) = 462 ways
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Cheers,
Stan H.