Question 593992
Write the standard form of the equation from the line that passes through points (-6,-8) and (-4,-11).

I have found the slope = -3/2
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Use y = mx + b and either point to find b, the y-intercept
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-8 = (-3/2)*(-6) + b
b = -17
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The eqn is y = (-3/2)x - 17
3x + 2y = -34 in standard form