Question 593567
solve the equation and approximate three deciaml places. 
1nx+1n(x+1)=1
ln[x(x+1)]=1
convert to exponential form:
e^1=x^2+x
x^2+x-e=0
solve by quadratic formula
a=1, b=1, c=-e≈-2.718
x=-2.223 (reject,x>0)
or
x=1.223