Question 593912
jASON HAD TO SUBMIT 5 PROJECTS. HE SCORED 88,79,76 AND 90 POINTS OUT OF 100 ON
4 PROJECTS. WHAT WOULD THE SCORE BE ON THE FIFTH PROJECT SO THAT THE AVERAGE IS 83?

{{{(88+79+76+90+x)/(5)}}}=83
{{{(333+x)/(5)}}}=83
333+x = (83)(5)
333+x) = 415
x=415-333
x=82
.
check by plugging 82 back into the equation (let x=82).