<PRE><B>Question 593903</B>
One painter works 1 1/2 times as fast as a second painter.?
Find their individual times for painting a room if, working together, they can complete the job in 4 hours.
:
Let t = time required by one painter to do the job
then
1.5t = time required by the other painter
:
Let the completed job = 1 (a painted room)
:
A shared work equation
{{{4/t}}} + {{{4/(1.5t)}}} = 1
Multiply by 3t to clear the denominators
3t*{{{4/t}}} + 3t*{{{4/(1.5t)}}} = 3t(1)
Cancel the denominaors
3(4) + 2(4) = 3t
12 + 8 = 3t
t = {{{20/3}}}
t = 6.67 hrs working alone
and
1.5*6.66 = 10 hrs the slow painter working alone
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