Question 593629
Let
numbers are x and y
one number is 4 more than another
{{{x=y+4}}}...........(1)
The difference between their squares is 80
{{{x^2-y^2=80}}}..........(2)
put the value of x from (1) to (2)
{{{(y+4)^2-y^2=80}}}
{{{y^2+8y+16-y^2=80}}}
{{{cross(y^2)+8y+16-cross(y^2)=80}}}
{{{8y+16=80}}}
{{{8y=80-16}}}
{{{8y=64}}}
{{{8y/8=64/8}}}
{{{cross(8)y/cross(8)=cross(64)/cross(8)}}}
{{{y=8}}}
Put the value of y in (1)
{{{x=y+4}}}...........(1)
{{{x=8+4}}}
{{{x=12}}}

Numbers are 12,8