Question 593378
<pre>
What you did was the correct FIRST STEP 
but you haven't finished:

{{{log(2,(8sqrt(y)))}}}
 
{{{log(2,(8))}}} + {{{log(2,(sqrt(y)))}}}

Write 8 as 2³ and {{{sqrt(y)}}} as {{{matrix(2,1,"",y^(1/2))}}}


{{{log(2,(2^3))}}} + {{{log(2,(matrix(2,1,"",y^(1/2))))}}}

Now use this rule of logs on both terms: {{{log(B,(A^C))}}} = {{{C*log(B,(A))}}}  

{{{3log(2,(2))}}} + {{{expr(1/2)log(2,(y))}}}

On the first term use the rule:  {{{log(B,(B))=1}}}

{{{3(1)}}} + {{{expr(1/2)log(2,(y))}}}

3 + {{{1/2}}}log<sub>2</sub>(y)

Edwin</pre>