<PRE><B>Question 593367</B>
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The side of the large square can be represented by *[tex \LARGE x] and the side of the smaller square can be represented by *[tex \LARGE x\ -\ 2].  The area of the first square is then *[tex \LARGE x^2] and the area of the second square is *[tex \LARGE x^2\ -\ 4x\ +\ 4].  The difference between the two areas is 220, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ (x^2\ -\ 4x\ +\ 4)\ =\ 220]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE x\ -\ 2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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