<PRE><B>Question 593362</B>
3ln( e^2 - e ) - 3


3ln( e(e - 1) ) - 3


3( ln(e) + ln(e-1) ) - 3


3ln(e) + 3ln(e - 1) - 3


3 + 3ln(e - 1) - 3


3ln(e - 1)



So  3ln( e^2 - e ) - 3 = 3ln(e - 1)


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