Question 55455
The trickiest part about these kinds of problems is, of course, translating the prose to algebra. Let n = the number.

Three times (3X) the sum (+) of twice a number (2n) and 6...3(2n+6) is (=) four times (4X) two less than the number (n-2)...4(n-2).  Putting it all together:

3(2n+6) = 4(n-2) Simplify and solve for n.
6n+18 = 4n-8 Collect like-terms.
2n = -26 Divide both sides by 2.
n = -13

Check:
3(2(-13)+6) = 3(-26+6) = 3(-20) = -60
4(-13-2) = 4(-15) = -60

The number is -13