Question 593147
{{{sqrt(11x+3) +4x=18}}}

{{{sqrt(11x+3) =-4x+18}}}

square both sides

{{{11x+3 = (18-4x)^2}}}


{{{11x+3= 324-144x+16x^2}}}


{{{16x^2-144x-11x+324-3=0}}}

{{{16x^2-155x+321=0}}}


Find the roots of the equation by quadratic formula								
								
a=	16	,	b=	-155	,	c=	321	
								
b^2-4ac=	24025	+	-20544					
b^2-4ac=	3481		
{{{	sqrt(	3481	)=	59	}}}
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	155	+	59	)/	32			
x1=	6.69							
x2=(	155	-59	) /	32				
x2=	3.00							


(6.69 OR 3)