Question 593131
Wow, you have one nice math question here!

question: 6x^2+19x+10

1. You have to try to get rid of the six, however, that would cause a major problem since it makes everything into fractions, which is harder to solve.

2. Lets do the basic and easy way without problems

6x^2+19x+10

6x      
x
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hmmm...this doesn't work out, right?

lets use the quadratic equation now

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

plug everything in

{{{x = (-19 +- sqrt( 19^2-4*6*10 ))/(2*6) }}}

{{{x = (-19 +- sqrt( 361-240 ))/(12) }}}

{{{x = (-19 +- sqrt(121))/(12) }}}

Now you have two answers:

-30/12 = -15/6 and -8/12 = -4/6 = -2/3

These two solutions do not exist, so the solution is impossible