Question 592787
I'm assuming you want to factor.




{{{x^3+5x^2-16x-80}}} Start with the given expression



{{{(x^3+5x^2)+(-16x-80)}}} Group the terms in two pairs



{{{x^2(x+5)-16(x+5)}}} Factor out the GCF {{{x^2}}} out of the first group. Factor out the GCF {{{-16}}} out of the second group



{{{(x^2-16)(x+5)}}} Since we have the common term {{{x+5}}}, we can combine like terms



{{{(x-4)(x+4)(x+5)}}} Now factor {{{x^2-16}}} to get {{{(x-4)(x+4)}}} by using the difference of squares formula.



So {{{x^3+5x^2-16x-80}}} factors to {{{(x-4)(x+4)(x+5)}}}



In other words, {{{x^3+5x^2-16x-80=(x-4)(x+4)(x+5)}}} for all values of x.



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