<PRE><B>Question 592562</B>
&lt;font face=&quot;Times New Roman&quot; size=&quot;+2&quot;&gt;


If *[tex \LARGE 7] is a root, then *[tex \LARGE x\ =\ 7] which is to say *[tex \LARGE x\ -\ 7\ =\ 0] which is to say *[tex \LARGE x\ -\ 7] must be a factor of the polynomial.


Likewise you can show that *[tex \LARGE 3x\ +\ 2] is a factor.


Therefore


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ 7)(3x\ +\ 2)\ =\ 0]


is the factored form of your quadratic.  All you have to do now is FOIL the two binomials.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
&lt;div style=&quot;text-align:center&quot;&gt;&lt;a href=&quot;http://outcampaign.org/&quot; target=&quot;_blank&quot;&gt;&lt;img src=&quot;http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png&quot; border=&quot;0&quot; alt=&quot;The Out Campaign: Scarlet Letter of Atheism&quot; width=&quot;143&quot; height=&quot;122&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;/font&gt;</PRE>