Question 55403
A linear equation has the form of y=mx+b where m = the slope of the line and b = the y intercept.  Right now we know the slope 3/4 and we know one point that the line passes through (10,-2).  Since the slope is defined as the rise over the run also known as the change in y over the change in x.  This can be stated as (y1-y2)/(x1-x2) for the points (x1,y1) and (x2,y2).  In our case our points are (10,-2) and (x2,y2) so the equation would look like
(-2-y2)/(10-x2)=3/4 since we are looking for the y intercept we know the x coordinate would zero, so the equation now looks like
(-2-y2)/(10-0)=3/4  Now lets simplify by multiplying both side by 10
(-2-y2)=30/4  Now multiply both sides by 4
4(-2-y2)=30  Simplify
-8-4y2 =30  Add 8 to both sides
-4y2=38  Divide both sides by -4
y2=-38/4  or y2=-9.5  Therefore the equation would be as follows
y = (3/4)x - 9.5