Question 592454
{{{3x^2 + 9xy + 4x + 12y}}}


{{{(3x^2 + 9xy) + (4x + 12y)}}}


{{{3x(x + 3y) + (4x + 12y)}}}


{{{3x(x + 3y) + 4(x + 3y)}}}


{{{(3x+4)(x + 3y)}}}



So {{{3x^2 + 9xy + 4x + 12y}}} completely factors to {{{(3x+4)(x + 3y)}}}


In other words, {{{3x^2 + 9xy + 4x + 12y=(3x+4)(x + 3y)}}} for all values of x and y