<PRE><B>Question 592255</B>
One day Mayan covered a distance of 24 km at x km/hr and another 40 km at y km/hr.
 Next day he covered 18 km at x km/hr and another 48 km at y km/hr.
 If each day he took 9 hours to complete his journey, find the corresponding values of speed of x and y.
:
Write a time equation for each day
:
{{{24/x}}} + {{{40/y}}} = 9
and
{{{18/x}}} + {{{48/y}}} = 9
:
Multiply the 1st equation by 1.2, subtract the 2nd equation
{{{28.8/x}}} + {{{48/y}}} = 10.8
{{{18/x}}} + {{{48/y}}} = 9
---------------------------subtraction eliminates y
{{{10.8/x}}}} + 0 = 1.8
10.8 = 1.8x
x = {{{10.8/1.8}}}
x = 6 km/hr 
:
Find the y using the 1st day equation
{{{24/6}}} + {{{40/y}}} = 9
4 + {{{40/y}}} = 9
{{{40/y}}} = 9-4
40 = 5y
y = 40/5
y = 8 km/hr
:
:
Check solutions in the 2nd day equation
:
{{{18/6}}} + {{{48/8}}} = 9
3 + 6 = 9
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