Question 55397
The book is asking me to match a graph to an equation. How do I take y-4=-(3/2)(x+1) and read it as a graph? I see a graph that has a point at the coordinates (1,-4) and a different one at (-1,4). 
{{{y-4=-(3/2)(x+1)}}}  is in point slope form {{{highlight(y-y1=m(x-x1))}}}, where m=slope and (x1,y1) is a point of the graph.
{{{y-highlight(4)=-(3/2)(x-highlight(-1))}}}
Your (x1,y1) is (-1,4), so pick that graph.
Here's what it should look like:
{{{graph(300,200,-10,10,-10,10,-(3/2)(x+1)+4)}}}
Happy Calculating!!!