Question 591610
Liquids A and B are mixed in the ratio 2:7 (by volume).
 What volume of liquid would be present in the solution if it contained 56 ml of liquid B? 
:
A ratio equation to find the amt of liquid A
:
{{{A/56}}} = {{{2/7}}}
Cross multiply
7A = 56 * 2
7A = 112
A = 112/7
A = 16 ml
:
Total volume: 56 + 16 = 72 ml