Question 591535
a. For b=2, solve for n ( that is, solve for n in the equation 2^x=e^nx.)
{{{2^x = e^(nx)}}}
{{{ln(2^x) = ln(e^(nx))}}}
log equiv of exponents, ln(e) = 1
x*ln(2) = nx
divide both side by x
ln(2) = n
n = .693
:
b Write a formula to determine n given any b.
n = ln(b)