Question 590960
<pre>
Given:

  AC &#8773; DC      

  BC &#8773; CE

To prove:

&#5123;ABC = &#5123;DEC

{{{drawing(1000/3,400,-.5,5.5,-2.5,2.5,
line(0,0,5,-1),line(0,-2,5,1),
line(0,0,0,-2), line(5,1,5,-1),
locate(0,0.2,B), locate(0,-2,A), locate(5,1.2,D), locate(5,-1,E),
locate(2.4,-.3,C)


 )}}}

1. AC &#8773; DC                 1,  Given

2. &#8736;ACB = &#8736;DCE             2.  They form a vertical pair.

3. BC = CE                 3.  Given

4. &#5123;ABC = &#5123;DEC             4.  SAS

Edwin</pre>