Question 55312
I'm using the following formula:
P(n,T) =(mu*T)^n][e^(-muT)]/n!
Your mu is 2; your T = 1 hr. ; your n=5
 
Actual arrivals in one hour were 2.
P(5 arrivals in one hour) = (2(1))^5 e^(-2(1))/5!
=[32e^-2]/120
=[32]/[120e^2]
=0.0361
Cheers,
Stan H.