Question 590906
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(3,4\right)]. So this means that {{{x[1]=3}}} and {{{y[1]=4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(1,2\right)].  So this means that {{{x[2]=1}}} and {{{y[2]=2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2-4)/(1-3)}}} Plug in {{{y[2]=2}}}, {{{y[1]=4}}}, {{{x[2]=1}}}, and {{{x[1]=3}}}



{{{m=(-2)/(1-3)}}} Subtract {{{4}}} from {{{2}}} to get {{{-2}}}



{{{m=(-2)/(-2)}}} Subtract {{{3}}} from {{{1}}} to get {{{-2}}}



{{{m=1}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(3,4\right)] and *[Tex \LARGE \left(1,2\right)] is {{{m=1}}}


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