Question 590754
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Divide *[tex \LARGE 2x^2\ +\ x\ -\ 6] by *[tex \LARGE x\ +\ 2] using Polynomial Long Division.  Alternatively, factor *[tex \LARGE 2x^2\ +\ x\ -\ 6].  One of the factors will be *[tex \LARGE x\ +\ 2] and the other will be the expression for your missing dimension.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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