Question 590442
1/3(6)^(-4x)+1=6 

i think your equation is this:

{{{(1/3)*(6)^(-4x)+1 = 6}}}


if so, then you would solve it as follows:


subtract 1 from both sides of the equation and then multiply both sides of the equation by 3 to get:


{{{(6)^(-4x) = 15}}}


take the log of both sides of this equation to get:


{{{log((6)^(-4x)) = log((15))}}}


since log(x^a) = a*log(x), this equation becomes:


{{{-4x * log((6)) = log((15))}}}


divide both sides of this equation by {{{log((6))}}} to get:


{{{-4x = log((15))/log((6))}}}


this becomes:


-4x = 1.511391594


divide both sides of this by -4 to get:


x = -.0377847899