Question 590108
ln3x-ln15=2

How i tried to solve: 

ln3x-ln15=2

ln3x divided by ln 15 = 2
It says minus, you can't change it to divide.
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ln3x-ln15=2
Logs are exponents.  Subtracting exponents --> dividing the arguments.
--> ln(3x/15) = 2
ln(x/5) = 2
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The base of ln's, natural logs, is e.
{{{e^(ln(x/5)) = e^2}}}
{{{x/5 = e^2}}}
{{{x = 5*e^2}}}
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then i crossed out ln with e  
divided the 15 & 3 =5x
and i got x=2 over 5 e