Question 55184
When a line have x-intercept -3 and y-intercept 5, the line passes through the points (-3,0) and (0,5).
So, the slope of the line,m= (5-0)/((0-(-3))=5/3, 
using the formula m=(y2-y1)/(x2-x1).
When the other line is parallel to the above line, slope is the same.
So,m=5/3
The equation of the second line is y=(5/3)x+b
When it passes through the point (6,1),
1=(5/3)*6+b
1=10+b
b=-9
The required equation of the line is
y=(5/3)x-9