<PRE><B>Question 55212</B>
The owner of a highway construction company knows that the maximum load a cylindrical column of a circular cross section can support varies directly as the fourth power of the diameter and inversely as the square of the height. 
If a column 2 feet in diameter and 10 feet high supports up to 6 tons, how much of a load can a column 3 feet in diameter and 14 feet high support?
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L=k(d^4/h^2)
need to find &quot;k&quot;
6 tons lbs. = k(2^4/10^2)
k=600/16=37.5
EQUATION:
Load = (37.5)(d^4/h^2)
Load = (37.5)(3^4/14^2)
=(37.5)(81/196)
=15.497... tons
Cheers,
Stan H.</PRE>