Question 55199
Find the center and the radius of the circle whose equation is given: x^2+y^2+6x+8=0
[X^2+2(X)(3)+3^2]-3^2+Y^2+8=0
(X+3)^2+Y^2=1
COMPARING WITH STD EQN.
(X-H)^2+(Y-K)^2 =R^2
CENTRE = (H,K) = (-3,0)
RADIUS =R =1


Center = (_,_) Radius = _