Question 586647
A smaller commuter airline flies to three cities whose locations form a vertices of a right triangle. The total flight distance( from city A to city B to city C and back to city A) is 1400 miles. It is 600 miles between the two cities that are furthest apart. Find the other two distances between cities
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The hypotenuse = 600 miles
The other 2 legs, a & b, add to 800 miles
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a + b = 800
b = 800 - a
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{{{a^2 + b^2 = 600^2}}}
{{{a^2 + (800-a)^2 = 600^2}}}
{{{2a^2 - 1600a + 640000 = 360000}}}
{{{a^2 - 800a + 140000 = 0}}}
*[invoke solve_quadratic_equation 1,-800,140000]