Question 588637
An object is propelled straight down with an initial velocity of 60 feet per second, from a height of 6,000 feet. How high is the object after 15 seconds?
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Using 32 ft/sec/sec for Earth's gravitational acceleration:
h(t) -16t^2 - 60t + 6000
h(3) = -16*9 - 60*3 + 6000
h(3) = 5676 feet