Question 587588
{{{3(2a-1)<4(2a-3)}}} Start with the given inequality.



{{{6a-3<8a-12}}} Distribute.



{{{6a<8a-12+3}}} Add {{{3}}} to both sides.



{{{6a-8a<-12+3}}} Subtract {{{8a}}} from both sides.



{{{-2a<-12+3}}} Combine like terms on the left side.



{{{-2a<-9}}} Combine like terms on the right side.



{{{a>(-9)/(-2)}}} Divide both sides by {{{-2}}} to isolate {{{a}}}. note: Remember, the inequality sign flips when we divide both sides by a negative number. 



{{{a>9/2}}} Reduce.



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Answer:


So the solution is {{{a>9/2}}} 



The answer in interval notation is *[Tex \LARGE \left(\frac{9}{2},\infty\right)]

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