Question 587955
Get the value of q in the equation {{{ 3/(5*q)-2*(q+3)/(3*q)=1+2/q }}}
:
{{{ 3/(5q)}}}- {{{2*(q+3)/(3q)}}}={{{1+2/q }}}
Multiply by 15q to clear the denominators, results
3(3) - 10(q+3) = 15q + 15(2)
:
9 - 10q - 30 = 15q + 30
-10q - 21 = 15q + 30
-10q - 15q = 30 + 21
-25q = 51
q = {{{51/(-25)}}}
q = {{{-51/25}}}