Question 587956
9=a(2)^n ___ log(9) = log(a) + n log(2)


4=a(3)^n  ___ log(4) = log(a) + n log(3)


subtracting ___ log(9) - log(4) = n log(2) - n log(3) ___ log(9/4) = n log(2/3)


log[(2/3)^-2] = n log(2/3) ___ -2 log(2/3) = n log(2/3) ___ -2 = n


substituting ___ 9 = a(2^-2) ___ 9 = a(1/4) ___ 36 = a