Question 587871
a=	5	,	b=	3	,	c=	-2	
								
b^2-4ac=9+40	
				
b^2-4ac=49		

sqrt(49)=7

x=(-b+-sqrt(b^2-4*a*c))/(2*a)
								
x1=(-b+sqrt(b^2-4*a*c))/(2*a)								
x1=(-3+	7)/10			
x1=	0.40	
						
x2=(-3-7) /10				
x2=	-1.00