Question 587391
Set up two equations: the first for the % solution and the second for the amount (gallons).  x = gallons of the first solution, and y = gallons of the second solution.<P>
Gallons:  x+y=20 s0 x = 20-y
Solution: .1x +.3y = .22*20 = 4.4 | Substitute the x value from the first eq: 20-y
.1(20-y) + .3y = 4.4
2-.1y+.3y = 4.4
.2y = 2.4
y =12<P>
From the first equation x = 20-y = 20-12 = 8.<P>
8 gallons of the 10% solution and 12 gallons of the 30% solution.<P>
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