Question 55150
When using the quadratic formula to solve a quadratic equation ax2 + bx + c = 0, the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative. (When the discriminant is negative, then we have the square root of a negative number. This is called an imaginary number, sqrt(-1) = i. )
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Explain what the value of the discriminant means to the graph of y = ax2 + bx + c. Hint: Chose values of a, b and c to create a particular discriminant.  Then, graph the corresponding equation. 
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When the discriminant is positive there are two real solutions.  (Two places the graph crosses the x-axis.
{{{0=x^2+5x+6}}}
has a discriminant of {{{5^2-4(1)(6)=1}}}  1 is positive and the solution is: x={-3,-2} and the graph y=x^2+5x+6 crosses the x-axis at -3 and -2.
{{{graph(300,200,-10,10,-5,5,x^2+5x+6)}}} 
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When the discriminant is 0, there is one real solution and the graph barely touches the x axis in one place.
{{{0=x^2+4x+4}}}
has a discriminant of 
{{{4^2-4(1)(4)=0}}} and the real solution is x=-2 and the graph of y=x^2+4x+4 barely touches the x axis in one place x=-2
{{{graph(300,200,-10,10,-10,10,x^2+4x+4)}}}
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When the discriminant is negative there are two imaginary solutions and the graph doesn't cross the x-axis.
{{{0=x^2+2x+4}}}
has a discriminant of {{{2^2-4(1)(4)=-12}}} and has two imaginary solutions, {{{-2+-sqrt(3)i}}}.  Double check that-I didn't write it down to solve it with the quadratic equation, but you didn't ask for that.  It was a freebie.
The graph looks like:
{{{graph(300,200,-10,10,-10,10,x^2+2x+4)}}} 
Happy Calculating!!!