Question 587366
odd integers:

2n+1, 2n+3

(2n+1)(2n+3) = 899

4n^2 + 8n + 3 = 899

4n^2 + 8n + 3 - 899 = 0

4n^2 + 8n - 896 = 0

n^2 + 2n - 224 = 0 

*[invoke quadratic "x", 1, 2, -224 ]

plugging either of the roots in for n gives

29 and 31

29 x 31 = 899