Question 587256
(w3 + 64) ÷ (4 + w) 

a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16
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You can try each answer, see which is correct, if any.
Or, divide and see what that answer is.
{{{(w^3 + 64)/(w+4)}}}
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Look at the sum of 2 cubes:
{{{a^3 + b^3 = (a+b)*(a^2 - ab + b^2)}}}