Question 587178
please help me solve for x algebraically:
log subscript 2 x + log subscript 2 (x+2) -log sub script 2 (4-x)=2 
.
{{{log(2,x) + log(2,x+2) - log(2,4-x) = 2}}}
{{{log(2,x(x+2)) - log(2,4-x) = 2}}}
{{{log(2,x(x+2)/(4-x)) = 2}}}
{{{x(x+2)/(4-x) = 2^2}}}
{{{x(x+2)/(4-x) = 4}}}
{{{x(x+2) = 4(4-x)}}}
{{{x^2+2x = 16-4x}}}
{{{x^2+6x = 16}}}
{{{x^2+6x-16 = 0}}}
{{{(x+8)(x-2) = 0}}}
x = {-8, 2}
We throw out the negative solution (extraneous) leaving:
x = 2