Question 55131
I think what you intended to write is {{{(y^2 - 2y)/(y^2-y-2)}}}.

{{{(y^2 - 2y)/(y^2-y-2)}}}
= {{{y(y - 2)/(y^2-2y + y -2)}}}
= {{{y(y - 2)/(y(y-2) + 1(y -2))}}}
= {{{y(y - 2)/((y+1)(y-2))}}}
= {{{y/(y+1)}}} [if y is not equal to 2]