Question 586833
working the first two terms as the difference of squares


(3x - 5)(x + 3) + 12x - 60 = 0 ___ 3x^2 + 4x - 15 + 12x - 60 = 0 ___ 3x^2 + 16x - 75 = 0


factoring ___ (3x + 25)(x - 3) = 0


the answer that you know, is not correct


you can plug x=5/-5 into the original equation, and see that it does not work