Question 586750
how do i solve: log base 2 8   (log2 8)
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If you mean
{{{log(2,(8*log(2,8)))}}}
= {{{log(2,(log(2,8^8)))}}}
= {{{log(2,(log(2,2^24)))}}}
= {{{log(2,24)}}}
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For a numerical answer:
= log(24)/log(2)
=~ 4.58496