Question 586676
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Since L is the midpoint, CL = LD.  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{3}x\ +\ 8\ =\ \frac{2}{3}x\ -\ 4]


Solve for *[tex \LARGE x].  Use the value of *[tex \LARGE x] to calculate either the measure of CL or LD then multiply that value by 2.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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