Question 586639
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{y}\ =\ \frac{2}{5}]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ -\ 5}{y\ -\ 5}\ =\ \frac{1}{4}]


so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x\ =\ 2y]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ -\ 20\ =\ y\ -\ 5]


Solve the 2X2 system.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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