<PRE><B>Question 586578</B>
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Polygons do not have internal &lt;i&gt;&lt;b&gt;angels&lt;/b&gt;&lt;/i&gt; or angels of any sort, for that matter.  If you want to ask questions about &lt;i&gt;&lt;b&gt;angels&lt;/b&gt;&lt;/i&gt;, please direct them to the local clergyman who practices a faith commensurate with your personal values.


The sum of the measures of the internal angles of an *[tex \LARGE n]-gon is given by *[tex \LARGE 180(n\ -\ 2)].  If the polygon is a regular polygon, each of the internal angles measures:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{180(n\ -\ 2)}{n}]


For you, *[tex \LARGE n\ =\ 6].  Do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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